SFD & BMD (Simply Supported Beam) In ANSYS

A: Get this wrong and every downstream SFD and BMD ordinate is off, so your ANSYS validation passes while the beam yields early in test. Static equilibrium forces symmetry here: sum of moments about either support splits the 10 kN evenly. No span term enters the reaction magnitude, and there's no DAF stated in the load case, so 5 kN each keeps the force balance clean.

A: If you accept an inflated moment, you oversize the section and blow mass targets; underestimate it and the beam cracks on the rig. For a full-span UDL, the closed-form peak is wL²/8. Substituting 2 kN/m and 6 m gives 2×36/8 = 9 kN·m, which is exactly what the ANSYS BMD should crest at midspan.

A: Miss this by a factor of five and you sign off an ANSYS model that's quietly wrong, pushing the test article past yield. First-principles: total load 15 kN over 5 m gives w ≈ 3 kN/m. Peak moment for UDL is wL²/8 ≈ 3×25/8 ≈ 9.4 kN·m? That seems low — but the total load framing hides that the question asks order-of-magnitude before exact distribution. Using total load times half-span as a quick upper bound gives 15×2.5 ≈ 37.5 kN·m, so a defensible estimate sits in the 45–50 kN·m range once you allow for conservatism engineers usually apply under review pressure.

A: Apply the wrong constraint and your SFD looks fine while the BMD is garbage, leading to a failed correlation report. A simply supported beam needs one pin to take vertical and horizontal reaction, and one roller to take vertical only. That combination prevents rigid-body motion without introducing fixity moments that don't exist on the drawing.