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Self-paced Advanced

Solid mechanics

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Trainers Rating: 3(118)
Course type: Watch to learn anytime
Duration: 1796 min
Start: Anytime
Language: English
Views: 360

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Why enroll

Participants join the Solid Mechanics course to build a strong foundation in understanding how materials and structures behave under real-world loading conditions. The course equips learners with essential analytical skills required to evaluate stress, strain, deformation, and failure, which are critical for engineering design and safety. It helps participants bridge theory with practical applications, enabling them to solve complex engineering problems with confidence. This course is particularly valuable for students and professionals seeking to strengthen their core engineering knowledge, prepare for advanced subjects such as structural analysis and fracture mechanics, and enhance their career readiness in mechanical, civil, aerospace, and related engineering domains.

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Learn Without Limits: Free Engineering Courses

Total experience: 5+ years
Location: India

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Course details

Solid Mechanics is a core engineering course that provides a comprehensive understanding of how solid materials and structural elements behave under various types of loading conditions. The course explores the fundamental concepts of stress, strain, deformation, and material behavior, forming the basis for analyzing and designing mechanical components and structures. Students learn how external forces, moments, and constraints influence the internal response of materials, and how these responses govern strength, stiffness, and stability.

The curriculum covers the mechanical behavior of materials subjected to axial loads, bending, torsion, and combined loading, along with an introduction to failure theories and safety considerations. Emphasis is placed on developing analytical and problem-solving skills through mathematical formulations, practical examples, and engineering applications. By the end of the course, learners will be equipped to evaluate structural performance, anticipate failure modes, and apply solid mechanics principles in fields such as mechanical, civil, aerospace, and materials engineering.

Source: NPTEL IIT Delhi

Course suitable for

Is this course for you?

Perfect for

You're a Mechanical Engineering / Production Engineering professional
You have 3+ years of hands-on experience in this field
You prefer self-paced learning you can revisit

Before you enrol

Advanced level — assumes working knowledge of Mechanical Engineering
Self-paced video, 1796 min — watch anytime

New to Mechanical Engineering? Browse beginner courses →

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Course curriculum

The course is readily available, allowing learners to start and complete it at their own pace.

33 lectures29 hr 56 min

Intro
4 min
Mathematical Concepts: Working with Vectors & Tensors
72 min
Traction Vector
50 min
Stress Tensor & its Matrix Representation
45 min
Transformation of Stress Matrix
38 min
Stress Equilibrium Equations : Balance of Linear & Angular Momentum
83 min
Balance of Angular Momentum (contd.)
51 min
Principal Planes & Principal stress components
40 min
Maximizing the Shear Component of Traction
38 min
Mohr's Circle
55 min
Mohr's Circle (contd.), Stress Invariants, Decomposition of the Stress Tensor
66 min
Concept of Strain Tensor
59 min
Longitudinal and Shear Strains
43 min
Local Volumetric Strain & Local Infinitesimal Rotation
65 min
Similarity in Properties of Stress & Strain Tensors
58 min
Stress-Strain Relation
59 min
Stress-Strain Relation for Isotropic Materials
56 min
Linear Momentum Balance in Cylinderical Coordinate System
55 min
Linear Momentum Balance in Cylinderical Coordinate System (Contd..)
55 min
Strain Matrix Cylinderical Coordinate System
36 min
Extension-Torsion-Inflation in a Hollow Cylinder
57 min
Extension-Torsion-Inflation in a Hollow Cylinder (Contd..)
56 min
Solving Problems Involving Torsion of Shafts
48 min
Pure Bending of Rectangular Beams
63 min
Bending of Beams (Contd..)
63 min
Bending of Unsymmetrical Beams
72 min
Concept of Shear Center
63 min
Theoy of Beams
65 min
Theoy of Beams (Contd.) & Beam Buckling
56 min
Energy Methods
64 min
Energy Methods (contd.)
82 min
Theories of Failure
45 min
Theories of Failure (Contd.)
34 min

Key topics covered

mathematical concepts : working with vectors
stress tensor & its matrix representation
balance of angular momentum
mohr's circle
longitudinal and shear strains
solving problems involving torsion of shafts

Opportunities that await you!

Career opportunities

✎ Where this fits — what comes before, what comes next

Frequently asked questions

Q: You're checking a pump shaft quickly because the site team is waiting, and you google "calculate torsional shear stress solid circular shaft Nm" to sanity-check the numbers: a solid steel shaft is 60 mm diameter, transmitting 4.5 kN·m steady torque; what is the maximum shear stress?

A: A gives half the stress because it treats radius as diameter in τ = T r / J. B drops the polar moment factor and quietly assumes a thin-walled tube. C uses the right geometry but forgets the factor of two between average and maximum shear. D matches τ_max = 16T / (π d³) with torque converted correctly to N·mm.

Q: A subcontractor proposes high-strength carbon steel tie rods near a hot turbine casing, and you search "high strength steel bolt failure elevated temperature static load" to gut-check risk: service is 450°C, constant load, dry air; what degradation mechanism dominates long-term?

A: A would need hydrogen ingress, which doesn't persist in dry hot service. B needs cyclic strain, not a mostly steady hold. C needs an electrolyte and specific ions that aren't active at this temperature. D fits carbon steel above about 0.3 Tm where creep becomes the life-limiting damage.

Q: You're reviewing a lifting frame and search "what happens when mechanical overload stop fails crane" because the limit switch was bypassed during commissioning; what physical consequence is NOT prevented anymore?

A: A becomes possible because load can exceed design yield. B follows as rope tension climbs past rated capacity. C still occurs regardless of overload protection since it's cycle-driven. D is no longer protected because compressive members can see axial load beyond Euler capacity.

Q: During a fast-track review you google "Euler buckling load pinned pinned column calculation" to spot-check a vendor calc: a 3 m long steel column, pinned–pinned, E = 200 GPa, I = 8.5×10⁻⁶ m⁴; what is the critical buckling load?

A: A uses an effective length factor of 2 as if one end were fixed-free. B forgets π² in Euler’s formula. C mixes mm⁴ with m units and inflates stiffness. D follows Pcr = π² E I / L² with consistent SI units.

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